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3 years ago

Plot the inequality x < 0

Mathematics

1 answer:

Sholpan [36]3 years ago

7 0

Step-by-step explanation:

This is saying " Every number possible thats less than, but not 0" so you show that

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Is this a bar above every interval? Explain why or why not.

Annette [7]

Answer:

No, because there is no data for the interval.

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3 years ago

IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?

mestny [16]

Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

5 0

3 years ago

The formula for the area of a square is A = sa, where s is the length of a side.

Sliva [168]

Answer:

$\sqrt{400} = 20$

Step-by-step explanation:

Since the sides of a square are equal, A = s x s so taking the square root of the square provides the length of each side

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2 years ago

From where Kiana is standing, she must look up at a 50° angle to see the top of a building. If she backs up 50 feet, she will ne

Morgarella [4.7K]

For this case, what we must do is solve the following system of equations:
tan (50) = h / x
tan (40) = h / (x + 50)
Solving the system we have:
(x + 50) * tan (40) = h
(x) * tan (50) = h
Matching:
(x + 50) * tan (40) = (x) * tan (50)
Rewriting:
x (tan (50) - tan (40)) = 50 * tan (40)
x = 50 * tan (40) / (tan (50) - tan (40))
x = 118.9692621
Substituting:
h = (x) * tan (50)
h = (118.9692621) * tan (50)
h = 141.7820455
Answer:
The height of the building is:
h = 141.7820455 ft

5 0

3 years ago

Read 2 more answers

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2

Plot the inequality x < 0​

Plot the inequality x < 0