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tatyana61 [14]
2 years ago
8

James has organised a game to raise money for charity at a local fair. He rolls a fair six sided dice and flips a fair coin. If

the coin lands on heads, the number on the dice is squared. If the coin lands on tails, the number on the dice is cubed. Each person pays 50p to play. If they score above 30, they win £1 The game is played 450 times. How much money does James raise for charity?​
Mathematics
1 answer:
Scorpion4ik [409]2 years ago
3 0

The total amount that was raised for charity is £75.

<h3>What is the total amount raised?</h3>

Here is the sample space

                  1               2            3            4            5           6

Heads        1               4            9           16            25        36

Tails           1               8            27          64           125        216

Probability of getting a number greater than 30 = 4/12 = 1/3

1/3 x 450 = 150

Total value of people getting more than 30 : 150 x £1 = £150

Total amount paid = 50 x 450 = £225

Amount raised = £225 - 150 = £75

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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15 is 60% of what number?
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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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mote1985 [20]

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Find the equation of a line parallel to −5x+y=2 that contains the point (5,−2). Write the equation in slope-intercept form.
mario62 [17]

Answer:

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

Step-by-step explanation:

Parallel lines have same slopes.

Line 1,   L1:  5x-2y=20   is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.

5x-2y = 20

-2y = -5x+20

y = (-5/-2)x+20/(-2)

y = (5/2)x-10 hence m1=5/2 and y-intercept is -10

Line 2 , L2:   y-y1 = m (x-x1),  m=m2=m1=5/2

Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

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