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FrozenT [24]
3 years ago
12

Mitchell needs to buy some wood to build a rectangular box that is 12 inches long 8 I ches wide and 10 inches high a net of the

box is shown how many square inches of wood would Mitchell need to build the box
Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

592 in²

Step-by-step explanation:

Given

Length of the box L = 12 inches

Width W = 8 inches

height H = 10inches

Required

Surface Area of the box

Surface area of the rectangular boss = 2(LW + LH + WH)

Substitute the given values

Surface area = 2(12(8)+12(10)+8(10))

Surface Area = 2(96+120+80)

Surface Area = 2(96+200)

Surface area = 2(296)

Surface area = 592 in²

Hence  592 in² of wood would be needed by Mitchell to build the box

bixtya [17]3 years ago
5 0

Answ

592 in²

Step-by-step explanation:

Given

Length of the box L = 12 inches

Width W = 8 inches

height H = 10inches

Required

Surface Area of the box

Surface area of the rectangular boss = 2(LW + LH + WH)

Substitute the given values

Surface area = 2(12(8)+12(10)+8(10))

Surface Area = 2(96+120+80)

Surface Area = 2(96+200)

Surface area = 2(296)

Surface area = 592 in²

Hence 592 in² of wood would be needed by Mitchell to build the box

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Answer:


Step-by-step explanation:

To find the best place to buy the video game, we need to find the price for each store, and see which is least. To do this, find the percents of each and subtract.

To find the percent, simply multiply your original number by a decimal version of the percent

Ex: 160* .4=64

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     160*.2=32.

Then, subtract the amounts from each price.

160-64=96

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Hope this helps!

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3 years ago
What is -2(X+1/4)+1=5
elena-s [515]
-2x + x/4 + 1 = 5
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4 years ago
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Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

7.94

3 0
3 years ago
Maria Cardenas had a policy with a $500 deductible which paid 80% of her covered charges less deductible. She had medical expens
Mariulka [41]
A.) The insurance company's payment is 80% of the total minus the $500 deductible, so:
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Brown’s time for running a mile in gym class is 9.9 minutes, Ray’s time is 9.47 minutes and Malcolm’s time is 9.76 minutes. Who
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Given:

Brown’s time for running a mile in gym class = 9.9 minutes

Ray’s time for running a mile in gym class = 9.47 minutes

Malcolm’s time for running a mile in gym class = 9.76 minutes

To find:

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Solution:

It is given that the time taken by Brown, Ray and Malcolm to cover a mile are 9.9 minutes, 9.47 minutes and 9.76 minutes respectively.

9.47 < 9.76 < 9.9

Since, 9.47 minutes is the lowest time, therefore Ray can run a mile in less time.

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