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zheka24 [161]
3 years ago
11

Find the value of 48 - 32 ÷ 4 · 2

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0

<span>48−<span>32÷4×2</span></span>

=<span>48−<span><span>32×2</span>4</span></span>

=<span>48−<span>8×2</span> or 48−<span>644</span></span>

=<span>48−16</span>

=<span>32</span>

Alla [95]3 years ago
4 0

Answer:

32

Step-by-step explanation:

We have been given an expression 48-32\div 4\cdot 2. We are asked to find the value of our given expression.

Using order of operations (PEMDAS), we will divide or multiply from left to right.

Dividing 32 by 4:

48-8\cdot 2

Multiplying 8 by 2:

48-16

32

Therefore, the value of our given expression is 32.

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Can someone help me out on this please having trouble on both and show work please !!
inysia [295]

The difference of the expression is as follows:

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5) = - 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4) = x - 19

<h3>How to find the difference of the expression?</h3>

The difference of the expression can be found when we combine the like terms.

Therefore,

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)

6y⁴ + 3y² - 7  - 12y⁴ + y² - 5

6y⁴ - 12y⁴ + 3y² + y² - 7 - 5

- 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4)

3x - 15 - 2x - 4

3x - 2x - 15 - 4

x - 19

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2 years ago
15. Robin ordered pizza and opted for delivery.
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Answer: No she'll need atlease 9 dollars

Step-by-step explanation:

48.95 x 18% is 8.811 which is greater than

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2 years ago
A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.
AVprozaik [17]

Answer:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean  is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

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3 years ago
A police department commissioned a door-to-door survey of citizens on whether they commit minor law infractions, such as speedin
Neko [114]

Answer: Interviewer-induced bias

Step-by-step explanation:

The example given in the question illustrates the Interviewer-induced bias. This occurs when the situation created by the interviewer is such that the respondent will have to give the kind f answer that the interviewer wants to hear.

For example, in the question, we can deduce that the interviewers told the interviewees that they won't be investigated and the gave bias replies based on that.

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