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zheka24 [161]
3 years ago
11

Find the value of 48 - 32 ÷ 4 · 2

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0

<span>48−<span>32÷4×2</span></span>

=<span>48−<span><span>32×2</span>4</span></span>

=<span>48−<span>8×2</span> or 48−<span>644</span></span>

=<span>48−16</span>

=<span>32</span>

Alla [95]3 years ago
4 0

Answer:

32

Step-by-step explanation:

We have been given an expression 48-32\div 4\cdot 2. We are asked to find the value of our given expression.

Using order of operations (PEMDAS), we will divide or multiply from left to right.

Dividing 32 by 4:

48-8\cdot 2

Multiplying 8 by 2:

48-16

32

Therefore, the value of our given expression is 32.

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Answer:

10 = c

Step-by-step explanation:

Distribute -4 to the parentheses:

8 = 8c - 4(c + 8)

8 = 8c - 4c - 32

Add like terms:

8 = 4c - 32

Add 32 to both sides:

40 = 4c

10 = c

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4 years ago
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An apprentice productively working a 40-hour week earns more wages and is worth considerably more to the local union and the ind
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$3.60

You can get this by determining that the rate of which they are paid is $4 an hour (divide the total by the amount of hours). Then you can find the rate of which they collect dues by dividing the amount they paid by their total (3%). 

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Weights ( in pounds) of catfish caught in the river:
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3 years ago
What is the solution to the equation? 2/3a -1/6=1/3
Monica [59]

Answer:

by2

a−2=

6

5

a

\frac{2}{3}a-\frac{5}{6}a=2

3

2

a−

6

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\frac{4a-5a}{6}=2

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#Learn more

Solve : 3a + 4/ 2 - 6a = -2/5

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3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
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