In the isosceles trapezoid below, x = [? ]° 5x-20° 2x+37°
1 answer:
You might be interested in
First let's solve the general case for an isosceles triangle of base 2 and height k. If the triangle is drawn so the base is on the x-axis and the apex is on the y-axis, the equation for the line containing the right side is
y = -k(x-1)
Then a rectangle with x-dimension w will have an area that is the product of this width and the height y = -k((w/2)-1).
area = w(-k(w/2 -1)) = (-k/2)w² +kw
The derivative of area with respect to w will be zero where the area is a maximum:
d(area)/dw = 0 = -kw +k
w = 1 . . . . . . add kw and divide by k
Using the formula for area, we find
area = 1(-k(1/2-1)) = k/2
This value is 1/2 the total area of the triangle we started with.
If the side lengths of your triangle are 8, √80, and √80, the height will be given by the Pythagorean theorem as
h = √((√80)² - (1/2·8)²) = √(80-16) = 8
Your triangle's area will be
triangle area = (1/2)(8)(8) = 32
The maximum area of the inscribed rectangle will be half this value,
16 square units
y = -k(x-1)
Then a rectangle with x-dimension w will have an area that is the product of this width and the height y = -k((w/2)-1).
area = w(-k(w/2 -1)) = (-k/2)w² +kw
The derivative of area with respect to w will be zero where the area is a maximum:
d(area)/dw = 0 = -kw +k
w = 1 . . . . . . add kw and divide by k
Using the formula for area, we find
area = 1(-k(1/2-1)) = k/2
This value is 1/2 the total area of the triangle we started with.
If the side lengths of your triangle are 8, √80, and √80, the height will be given by the Pythagorean theorem as
h = √((√80)² - (1/2·8)²) = √(80-16) = 8
Your triangle's area will be
triangle area = (1/2)(8)(8) = 32
The maximum area of the inscribed rectangle will be half this value,
16 square units
A. The value y-intercept represent in the context of the problem is 50.
B. The slope of the line is -10.
C. The equation to represent the line is y= -10x+50.
D. The number of customers in the restaurant at 8:30pm is 35.
<u>Step-by-step explanation:</u>
The equation of the line is given by y=mx+c.
y is the number of customers and x is the hours.
7.00 p.m. is considered as 0.
To find the slope m =
.
.
From the graph, choose two points. Let us take (0,50) and (4,10).
m=-10.
∴The equation can be written as y= -10x+c.
To find the y-intercept value c, substitute any point.
Let us substitute(0,50) for instance,
50=0+c.
c=50.
The equation for the given graph is y= -10x+50.
To find the customers at the restaurant at 8.30 pm.
we know that x=0 at 7.00 pm,
∴ x=1.5 can be considered as 8.30 pm.
Substitute x=1.5 in the line equation.
y= -10(1.5)+50.
y= -15-50.
y= 35.