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2 years ago

Which set of line segments can be used to construct a triangle?

Mathematics

1 answer:

RoseWind [281]2 years ago

4 0

Answer:A 2cm, 8cm and 9cm

Step-by-step explanation:

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After their hike, Joe and Mike took a taxi back to the trailhead. The taxi cost $26 plus $0.35 per mile. Which type of function

Sauron [17]

Answer:

The answer would be A. 1 1/5

Step-by-step explanation:

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

6 0

3 years ago

Solve.

lions [1.4K]

Answer:

b=9,a=12

Step-by-step explanation:

I solved by substitution:

b = 3/4a ---> plug this into the other equation

a + b = 21 is now a + 3/4a = 21

Reduce: 7/4a = 21

a = 12

Now solve for b:

b=3/4a is now b=3/4(12)

b=9

6 0

3 years ago

Read 2 more answers

Five times the sum of a number and 3 is 15

lara [203]

Answer:

the answer is 30 ok my friend your welcome

Step-by-step explanation:

3 0

2 years ago

program that generates two random numbers between one and 11. what is the probability that both values will be more than 7? numb

katovenus [111]

Answer:

1/9

Step-by-step explanation:

The numbers between 1 and 11 are:

2, 3, 4, 5, 6, 7, 8, 9, 10

There are 9 numbers.

Of the 9 numbers, 8, 9, and 10 are greater than 7, so there are 3 numbers greater than 7.

p(number greater than 7) = 1/3

p(>7) = 1/3

Each time a number is selected, the probability it is greater than 7 is 1/3.

For two numbers, you have two independent events, so the overall probability is the product of the individual probabilities.

p(>7 then >7) = p(>7) * p(>7) = 1/3 * 1/3 = 1/9

6 0

2 years ago

Will mark brainliest if answered fast enough

vekshin1

Answer:

Option D that is y=-2(x+1) is the correct choice.

Explanation:

Given equation:

$y=2x-2$

We have to find another equation which has only one solution.

Standard form of equation:

$1.a_1x+b_1y+c_1=0$

$2.a_2x+b_2y+c_2=0$

Condition for one solution.

$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$

We have to arrange other equation in the form of $ax+by+c=0$

Mark all the options as a,b,c and d.

$a.\ 2x+1-y=0$

$b.\ 2x-2-y=0$

$c.\ 2x-4-y=0$

$d.-2x-2-y=0$

Now from the above options we can see that option $a,b\ and\ c$ are not providing the desired result.

$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ can be obtained from the last option.

$\frac{a_1}{a_2} \neq \frac{b_1}{b_2} ,\frac{2}{-2} \neq \frac{-1}{-1} ,-1\neq 1$

Option D that is $y=-2(x+1)$ is the equation from where we can obtained only one solution.

4 0

2 years ago