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In-s [12.5K]
3 years ago
10

Which equation matches the function represented by the table?

Mathematics
1 answer:
bixtya [17]3 years ago
5 0

Answer:

the answer is a 0 b is x= -5 c is x = - 1.6 d is x= - 1.6

You might be interested in
12/19*.............................= -12/19
melamori03 [73]

Answer:

\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}

Step-by-step explanation:

\frac{12}{19} \times ..... = -\frac{12}{19}

= \frac{\frac{12}{19}}{-\frac{12}{19}}

= \frac{12}{19} \times -\frac{19}{12}

= -\frac{228}{228}

= \bold{-1}

So, the appropriate value to complete it is -1

#CMIIW ^^

3 0
3 years ago
Use two points to write an equation for the fuction shown.​
Rama09 [41]

Answer:

Step-by-step explanation:

100 is 4 times 25

25*4=100

so if we just multiply 26/25 we can find the percent

4*26/25=104/100

104%

8 0
2 years ago
The average person's head has about 100,000 strands of hair.
MrMuchimi

Answer:

B: 1 × 10^5

Step-by-step explanation:

B is correct and C is not becasue you have to have the number multiplied by 10 to a power because then you wouldn't know what number to use as the base. I hope this helps. :)

7 0
3 years ago
Read 2 more answers
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
What is the outlier of 29, 2, 28, 30, 26, 31
Vladimir [108]

Answer:

2

Step-by-step explanation:

Given the data : 29, 2, 28, 30, 26, 31

Outlier ;

Lower :Q1 - (1.5 * IQR)

Upper : Q3 + (1.5 * IQR)

Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range

Using calculator :

Q1 = 26

Q3 = 30

IQR = (Q3 - Q1) = 30 - 26 = 4

Lower : 26 - (1.5 * 4) = 20

Upper : 30 + (1.5 * 4) = 36

Hence, the number in the given data which falls outside the range is 2

4 0
3 years ago
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