Ask question

Ask question

All categories

1 year ago

10

a cylindrical container has a radius of 14 cm and I 20m high .it's curved surface is completely covered with a label . what is t

he area of the label in cm2 .take pie to be 22/7)

1 answer:

borishaifa [10]1 year ago

7 0

Answer:

The area of the label is 176,000 cm²

Step-by-step explanation:

The given parameters are;

The radius of the cylindrical container, r = 14 cm

The height of the cylinder, h = 20 m

The area covered with the label = The curved surface of the cylinder, A

The curved surface area of a cylinder, A = 2 × π × r × h

π = 22/7

∴ The curved surface area of the cylinder = A = 2 × 22/7 × 14 × 2000 = 176,000

A = 176,000 cm²

∴ The area of the label = The curved surface area of the cylinder = 176,000 cm².

You might be interested in

NEED HELP FAST!!

Dafna11 [192]

Answer:

see below

Step-by-step explanation:

dilation with a scale factor of 1/3 means the distances to the center shrink by 1/3

so for center (4,-2)

distance of (7,4) is 3 n 6 to center

1/3 of distance = 1 n 2

so (7,4) become (4+1, -2+2) = (5, 0) after the dilation

similarly u can find the other 2 pts

distance of (-2,4) is -6 n 6 to center

1/3 of distance = -2 n 2

so (-2,4) become (4-2, -2+2) = (2, 0) after the dilation

distance of (1, 10) is -3 n 12 to center

1/3 of distance = -1 n 4

so (1,10) become (4-1, -2+4) = (3, 2) after the dilation

plot the new triangle using the 3 pts

8 0

2 years ago

The mold for a cone has a diameter of 4 inches in 6 inches tall what is the volume of the cone mold to the nearest 10th

anygoal [31]

Hey there!

The formula for the volume of a cone is $V=\pi r^{2} \frac{h}{3}$ .

In this cone, we have the given information:

Its diameter is 4 inches
Its height is 6 inches

The information we need for this formula is the radius and height.

We already have the height, but not the radius.

Fortunately, we can easily get it by dividing the diameter by 2.

$4 \div 2 = 2$

So, the radius is 2.

Let 3.14 be $\pi$ .

Plug in each value into the equation. $V = 3.14 \times 2^{2} \times \frac{6}{3}$

Simplify the exponent and fraction.

$V = 3.14 \times 4 \times 2$

Multiply the three numbers together.

$V = 25.12$

But wait! We have to round this to the nearest tenth.

When rounding, we look at the place value one less than the one we are rounding to. Since we are rounding to the nearest tenth, we look at the hundredths place, which is the digit 2.

Since 2 is less than 5, we round down to 25.1.

This is the volume of a cube, and it is measured in inches, so the unit we will use is $in^{3}$ .

So, your <u>final answer</u> is $25.1 in^{3}$ !

Hope this helps!

8 0

2 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

2 years ago

ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports

iVinArrow [24]

Answer:

He have <u>15</u> action games and <u>24</u> sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be $x.$

As, given his action collection is three more than half his sports collection.

Thus, the action games = $3+\frac{x}{2}$ .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

$x+(3+\frac{x}{2})=39$

$x+3+\frac{x}{2} =39$

<em>Subtracting both sides by 3 we get:</em>

$x+\frac{x}{2} =36$

$\frac{2x+x}{2}=36$

$\frac{3x}{2} =36$

<em>Multiplying both sides by 2 we get:</em>

$3x=72$

<em>Dividing both sides by 3 we get:</em>

$x=24.$

<u>The sports games he have = 24.</u>

Now, to get the action games we substitute the value of $x$ :

$3+\frac{x}{2}$

= $3+\frac{24}{2}$

= $3+12$

= $15.$

<u>The action games he have = 15.</u>

Therefore, he have 15 action games and 24 sports games.

6 0

2 years ago

The complement of 4 heads in the toss of 4 coins is

Fofino [41]

Answer:

b i believe the answer is

4 0

2 years ago