Answer/Step-by-step explanation:
Part A:
![Key:\left[1 Adult = 4 Student]](https://tex.z-dn.net/?f=Key%3A%5Cleft%5B1%20Adult%20%3D%204%20Student%5D)
<u> 12 Student = 3 Adult</u>
<u>24 Student = 6 Adult</u>
<u>40 Student = 10 Adult</u>
Part B:
33 Student
Hence, divide 33 by 4 = 8 with a remainder of 1.
Therefore, 8 Adult and for the remainder 1 student either one Adult takes 5 Student or Needed 9 Adult.
X^2 = 6+5x => x^2 - 5x - 6 = 0 => (x-6)(x+1)=0
This riddle has two solutions:
x=6 or x=-1
indeed 6*6 = 36 = 5*6+6
indeed -1*-1 = 1 = 5*-1 + 6
The -1 is kind of a surprise, isn't it?
Y - x = 2x - 2/3y
y = 3x - 2/3y
1 2/3y = 3x
y = 1.8x
Answer:
try to use a calculator for it.
Step-by-step explanation:
Answer:
4845 ways
Step-by-step explanation:
We need to form groups of four students among the total of 20 students, and the order of the students inside the group does not matter, so we have a combination problem.
To solve this problem, we just need to find the combination of 20 choose 4:
C(20, 4) = 20! / (16! * 4!) = 20 * 19 * 18 * 17 / (4 * 3 * 2) = 4845
There are 4845 ways of selecting this group of four patrols.
