Question

How many grams of CaCl2 are in 0.75M solution with a volume of 1L

Answer 1

83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.

Explanation:

Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.

let us find the number of moles

n=C*V                Concentration is 0.75M

                          Volume is 1000ml.

n= 0.75*1

n= 0.75

This means there are 0.75 moles of CaCl2 in 1000 ml of solution of .75M.

Molar mass of CaCl2 is = 40.08+ 2(35.5)

                                       =   110.98 gms

Thus 1 MOLE OF CaCl2 weighs 110.98

         so 0.75 moles will weigh  110.98*0.75

                                              =  83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.