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storchak [24]
3 years ago
6

Can someone please help me, i put it at 40 points :) please help.

Mathematics
2 answers:
jonny [76]3 years ago
4 0

Answer:

5x + 2

Step-by-step explanation:

X is going to be the "number"

5 times the number

and then add two

Nataliya [291]3 years ago
3 0

Answer:

2 + 5 x n  

Hope this helps

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Rosa earns $500 after 25 hours of work. Fatima earns $600 after 30 hours of work. Who earned more per hour?
Brilliant_brown [7]

Answer:

C

Step-by-step explanation:

Rosa: 500/25 = 20

Fatima: 600/30 = 20

therefore the answer is C because the both earned the same amount

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IgorC [24]
<span>Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed in scientific notation?</span>
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4 years ago
Bank of America's Consumer Spending Survey collected data on annual credit card charges in seven different categories of expendi
cupoosta [38]

Answer:

a) Null hypothesis: \mu_d= 0

Alternative hypothesis: \mu_d \neq 0

b) t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{850 -0}{\frac{1123}{\sqrt{42}}}=4.905

The next step is calculate the degrees of freedom given by:

df=n-1=42-1=41

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v =2*P(t_{(41)}>4.905) =0.000015

So the p value is lower than any significance level given, so then we can conclude that we can reject the null hypothesis that the difference between he two groups are equal.

Step-by-step explanation:

Assuming the following questions:

We assume the following data: n = 42 ,\bar d= 850 , s_d = 1123

Previous concepts

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

a. Formulate the null and alternative hypotheses to test for no difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

The system of hypothesis for this case are:

Null hypothesis: \mu_2- \mu_1 = 0

Alternative hypothesis: \mu_2 -\mu_1 \neq 0

Or equivalently

Null hypothesis: \mu_d= 0

Alternative hypothesis: \mu_d \neq 0

b. Use a .05 level of significance. Can you conclude that the population means differ? What is the p-value?

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{850 -0}{\frac{1123}{\sqrt{42}}}=4.905

The next step is calculate the degrees of freedom given by:

df=n-1=42-1=41

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v =2*P(t_{(41)}>4.905) =0.000015

So the p value is lower than any significance level given, so then we can conclude that we can reject the null hypothesis that the difference between he two groups are equal.

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3 years ago
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Answer:

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I feel like there's not enough information to answer this question. was this the whole question?

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