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xxMikexx [17]
3 years ago
13

Angle Measurements 1”” degree help find out what’s the other side

Mathematics
1 answer:
Grace [21]3 years ago
8 0

Answer:

80 degree

Step-by-step explanation:

missing angle + 100 degree = 180 degree (being co interior angles )

missing angle = 180 - 100

missing angle 80 degree

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elena55 [62]

Answer:

C. 0.300 s.

53

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Step-by-step explanation:

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4 0
3 years ago
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DESPERATE WILL GIVE BRAINLIST AND THANKS
Illusion [34]

Answer: What you must do for this case is to graph each of the ordered pairs that you have in the table to obtain the dispersion chart. Note that in your table you have eight ordered pairs, therefore, your scatter chart must have eight pairs.

Step-by-step explanation:

7 0
2 years ago
Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF
Contact [7]

Find the equation of the inverse.

y =  {2}^{x + 5}  - 6

we have

y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6

step 1

Exchange the variables

x for y and y for x

x=\{2\}^{\{y+5\}}-6

step 2

Isolate the variable y

(x+6)=2^{(y+5)}

apply log both sides

\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\  \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}

step 3

Let

f^{(-1)}(x)=y

therefore

the inverse function is

f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5

7 0
1 year ago
Mr. Yasin paid a total of 9.43 to buy three boxes of cereal. If he paid 3.99 for the 1st box and 2.97 for the 2nd box how much d
Vikentia [17]

Answer:

$2.47

Step-by-step explanation:

Pretend if Mr. Yasin didn't pay for the 3rd box, find out how much he had left after paying for the first 2 boxes.

9.43 - 3.99 - 2.97 = 2.47

8 0
2 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
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