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Lera25 [3.4K]
3 years ago
15

X/12=8/y solve for x and y

Mathematics
1 answer:
ozzi3 years ago
6 0

Answer:y=20

Step-by-step explanation:y-12=8

Add 12 to both side’s of the equation

Y=8+12

Add 8 and 12

Y=20

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What is 95% off $780
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Answer:39

Step-by-step explanation:

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3 years ago
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What is the equation of the line that passes through the point (-5,-2) and has a slope of -6/5
tatyana61 [14]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 8  \\</h2>

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (-5,-2) and the slope is - 6/5

The equation of the line is

y + 2 =  -  \frac{6}{5} (x + 5) \\ y + 2  =  -  \frac{6}{5} x - 6 \\ y =  -  \frac{6}{5} x - 6 - 2

We have the final answer as

y =  -  \frac{6}{5} x - 8  \\

Hope this helps you

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4 years ago
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Natalija [7]

Select the second and fourth options.

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3 years ago
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3 years ago
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Given sin A = 12/13 and that angle A is in Quadrant 1,
UkoKoshka [18]

We have been given that \text{sin}(A)=\frac{12}{13} and angle A is in quadrant 1. We are asked to find the exact value of \text{cot}(A) in simplest radical form.

We know that sine relates opposite side of right triangle with hypotenuse.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

This means that opposite side is 12 units and hypotenuse is 13 units.

We know that cotangent relates adjacent side of right triangle with adjacent side.

\text{cot}=\frac{\text{Adjacent}}{\text{Opposite}}

Now we will find adjacent side using Pythagoras theorem as:

\text{Adjacent}^2=\text{Hypotenuse}^2-\text{Oppoiste}^2

\text{Adjacent}^2=13^2-12^2

\text{Adjacent}^2=169-144

\text{Adjacent}^2=25

Let us take positive square root on both sides:

\sqrt{\text{Adjacent}^2}=\sqrt{25}  

\text{Adjacent}=5

Therefore, adjacent side of angle A is 5 units.

\text{cot}(A)=\frac{5}{12}

Therefore, the exact value of cot A is \frac{5}{12}.

5 0
3 years ago
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