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Alexxx [7]
3 years ago
15

Cardinalul mulţimii A={ x  IN / x + 2 < 7 } este : a) 3 b) 4 c) 5 d) 6.

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
A few minutes ago he said that he had
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Hey! i’ll give brainliest help thanks
Setler [38]

Answer:

  • <u><em>to one's liking; pleasing: agreeable manners;an agreeable sensation. willing or ready to agree or consent: Are you agreeable to my plans for Saturday</em></u>
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Step-by-step explanation:

7 0
3 years ago
Please help me solve this problem?
Luden [163]

The problem statement gives a relation between the amount removed from one bag and the amount removed from the other. It asks for the amount remaining in each bag. Thus, there are several choices for variables in this problem, some choices resulting in more complicated equations than others.

Let's do it this way: let x represent the amount remaining in bag 1. Then the amount removed from bag 1 is (100-x). The amount remaining in bag 2 is 2x, so the amount removed from that bag is (100-2x). The problem statement tells us the relationship between amounts removed:

... (100 -x) = 3(100 -2x)

... 100 -x -3(100 -2x) = 0 . . . . . . subtract the right side

... 5x -200 = 0 . . . . . . . . . . . . . . eliminate parentheses and collect terms

... x -40 = 0 . . . . . . . . . . . . . . . . .divide by 5

... x = 40 . . . . . . . . . . . . . . . . . . . add 40

  • 40 kg is left in the first bag
  • 80 kg is left in the second bag

_____

<u>Check</u>

The amount removed from the first bag is 60 kg. The amount removed from the second is 20 kg. The amount removed from the first bag is 3 times the amount removed from the second bag, as described.


4 0
3 years ago
Given f(3)=7 and f(5)=252 write the first 6 terms of the sequence. no decimals
finlep [7]

\bf \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\\ f(2)&\\ f(3)&7\\ f(4)&7r\\ f(5)&7rr\\ &252\\ \cline{1-2} \end{array}\qquad \qquad 7rr=252\implies 7r^2=252\implies r^2=\cfrac{252}{7} \\\\\\ r^2=36\implies r=\sqrt{36}\implies r=6 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\stackrel{\frac{7}{6}\div 6}{\cfrac{7}{36}}\\ &\\ f(2)&\stackrel{7\div 6}{\cfrac{7}{6}}\\ &\\ f(3)&7\\ f(4)&42\\ f(5)&252\\ f(6)&1512\\ \cline{1-2} \end{array}

notice, once we know what the common factor "r" is, from the 3rd term we can simply multiply it by "r" to get the next term, and divide the 3rd term by "r" in order to get the previous term, namely the 2nd term, and then divide the 2nd by "r" to get the 1st one.

3 0
3 years ago
Which expressions are equivalent?
nasty-shy [4]
The first set of expressions bc 3x is equivalent to 3x and -7y is equivalent to -7y
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