So, since the polygons are similar, they will share a scale factor.
The dilation is a reduction.
SF= preimage/image
SF=48/40
SF= 1.2
To find the value of x, multiply 20 by 1.2, so:
20(1.2)=24
Thus, x = 24
Now, to check if the sides are proportional (this will determine if the polygons are, in fact, similar.)
24/20=1.2
48/40=1.2
BTW, the missing side measure for the image is 40 since 48 is its corresponding side, and 48/1.2 (SF) is 40.
Hence, we have 48/40= 1.2
<span>ʕ •ᴥ•ʔ</span>
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis :
H0 : μ = 3000
H0 : μ ≠ 3000
The test statistic :
(xbar - μ) ÷ (s/√(n))
xbar = 3500
μ = 3000
σ = 300
n = 30
(3500 - 3000) ÷ (350/√(30))
Test statistic = 7.824
Df = 30 - 1 = 29
Tcritical at 0.01 = 2.462
Test statistic > critical value ; we reject H0 ; and concluded that there is significant evidence that
μ ≠ 3000
Answer:
Step-by-step explanation:
(5x^3+4x^2)−(6x^2−2x−9)
To find the opposite of 6x^2−2x−9 find the opposite of each term.
5x^3+4x^2−6x^2+2x+9
Combine 4x^2 and 6x^2 to get −2x^2.
5x^3-2x^2+2x+9
step 1
<span>compute the average: add the values and divide by 6
Average =(44+ 46+40+34+29+41)/6=39
step 2
</span><span>Compute the deviations from the average
dev: (44-39)=5,
</span>dev: (46-39)=7
dev: (40-39)=1
dev: (34-39)=-5
dev: (29-39)=-10
dev: (41-39)=2
step 3
<span>Square the deviations and add
sum (dev^2): 5^2+7^2+1</span>^2+-5^2+-10^2+2^2
sum (dev^2): 25+49+1+25+100+4-----> 204
step 4
<span>Divide step #3 by the sample size=6
(typically you divide by sample size-1 to get the sample standard deviation,
but you are assuming the 6 values are the population,
so
no need to subtract 1, from the sample size.
This result is the variance
Variance =204/6=34
step 5
</span><span>Standard deviation = sqrt(variance)
standard deviation= </span>√<span>(34)------> 5.83
the answer is
5.83</span>
3x-8+6x=7
9x-8=7
9x=15
x=9/15
x=3/5
