SAS i believe :) sorry if im wrong!
the greatest is 10 and the least is one but I don't know for sure but I don't know if that what you looking for
Answer:
D
Step-by-step explanation:
A)
3(2) + 4(-2) = -2 2(2)-4(-2) = -8
6 - 8 = -2 4 + 8 = -8
Correct Incorrect
B)
3(6) + 4(-5) = -2 2(6) - 4(-5) = -8
18 - 20 = -2 12 + 20 = -8
Correct incorrect
C)
3(4) + 4(4) = -2
12 + 8 = -2
incorrect
D)
3(-2) + 4(1) =-2 2(-2) - 4(1) = -8
-6 + 4 = -2 -4 - 4 = -8
Correct Correct
Best way is process of elimination
Given that:
f(1)=13 and 2f(n-1)+(n-2)
then:
f(4) will be found as follows:
f(2)=2f(2-1)=2f(1)=2*13=26
f(3)=2f(3-1)+(3-2)=2f(2)+1=2*26+1=53
f(4)=2f(4-1)+(4-2)=2f(3)+(4-2)=2(53)+2=108
Thus:
Answer:(3) 108
