Question

Divide. (–6m 7 + 20m 6) ÷ 2m 4 A. –3m 3 + 20m 6 B. –3m 3 + 10m 2 C. –6m 7 + 20m 2 D. –3m 7 + 10m 6 Reset Selection

Answer 1

 ( –6m^7 + 20m^6) ÷ 2m^4 = ???

as you know

 –6m^7 + 20m^6 = 2m^4 (-3m^3 + 10m^2)

[2m^4 (-3m^3 + 10m^2) ] / 2m^4 (2m^4 is canceled out)

= -3m^3 + 10m^2

answer is B. –3m^3 + 10m^2

Answer 2

Answer:

B. -3m^7 + 10m^2

Step-by-step explanation:

First, we have to write down the division remembering that ÷ is the same as /

So we will write the division in terms of /

(-6m^7 + 20m^6) / 2m^4

This is the same equation as if we were using the symbol ÷

Now we have to remember the distribution when we are dividing fractions:

(a+b)/c = a/c + b/c ;

we can separate the fraction to make it easier, in this case:

a = -6m^7

b = 20m^6

c = 2m^4

And substituting in the fraction we have:

(-6m^7 + 20m^6) / 2m^4 = (-6m^7 / 2m^4) + (20m^6 / 2m^4)

We are going to use the second part:

(-6m^7 / 2m^4) + (20m^6 / 2m^4)

Now we are going to solve each parenthesis:

(-6m^7 / 2m^4)

To solve division that has variables with an exponent we have to remember the following:

ax^n / bx^m = (a/b) x^(n-m)

Where:

a and b are constant

x is the variable

and n and m are exponents

In the first parenthesis (-6m^7 / 2m^4):

(a/b) x^(n-m)

(-6/2) m^(7-4)

Now we solve and we have:

(-3) m^3 this is the first part of the division

Now we have to solve the second part of the division (20m^6 / 2m^4):

(a/b) x^(n-m)

(20/2) m^(6-4)

Now we solve:

(10) m^2 this is the second part of the division

Now we have to put the two parts together:

(-3m^3) + (10 m^2)