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OLEGan [10]
3 years ago
12

PLEASE HELP, question in image

Mathematics
2 answers:
Mashcka [7]3 years ago
4 0
You have the right answer but for the second part it's 65+10/5=x
svp [43]3 years ago
3 0

Answer:

(65+10)/5

You can simplify from 5x-10=65.

Sorry I was late I had to finish a quiz.

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780 as a percentage of 1.5
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780 as a percentage of 1.5
=\frac{780}{1.5} *100
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Fofino [41]

Answer:

$ 14.9

Step-by-step explanation:

we can create an equation

use variables:

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sauce = s

3.5p + 0.45s

3.5 (4) + 0.45(2)

<u>= $ 14.9</u>

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Write a fraction, a decimal, and a percent that sum to 1 or 100%.
NemiM [27]

Answer:

Fraction: 1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10 etc.

Decimal: 1.00

Percent: 100%

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3 years ago
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Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).
andre [41]
Check the picture below.  So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

\bf \textit{hyperbolas, vertical traverse axis }\\\\&#10;\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ({{ h}},{{ k}})\\&#10;vertices\ ({{ h}}, {{ k}}\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{{{ a }}^2+{{ b }}^2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;h=0\\&#10;k=0\\&#10;a=4\\&#10;c=5&#10;\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1&#10;\\\\\\&#10;c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\\\\\\&#10;\sqrt{5^2-4^2}=b\implies \boxed{3=b}&#10;\\\\\\&#10;\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}

7 0
4 years ago
The data below show the weights, in pounds, of a group of professional football players.
monitta

Answer:

The Mean Absolute Deviation is 11

Step-by-step explanation:

Given:

325, 310, 289, 288, 285, 285, 285, 280, 280 and 273

Mean = 290

Required:

Calculate the Mean Absolute Deviation

Provided that we have the value of the mean to be 290 from the question; the following steps will calculate the Mean Absolute Deviation

Step 1: Subtract the mean weight from each weight

325 - 290 = 35

310 - 290 = 20

289 - 290 = -1

288 - 290 = -2

285 - 290 = -5

285 - 290 = -5

285 - 290 = -5

280 - 290 = -10

280 - 290 = -10

273 - 290 = -17

Step 2: Calculate the absolute value of the each results above

|35| = 35

|20| = 20

|-1| = 1

|-2| = 2

|-5| = 5

|-5| = 5

|-5| = 5

|-10| = 10

|-10| = 10

|-17| = 17

Step 3: Calculate the mean of the data above

Mean Absolute Value = \frac{35 + 20 + 1 + 2 + 5 + 5 + 5 + 10 + 10 + 17}{10}

Mean Absolute Value = \frac{110}{10}

Mean Absolute Value = 11

Hence, the Mean Absolute Deviation is 11

3 0
3 years ago
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