Answer:
In a STAR TOPOLOGY network, each device on the network is attached to a central router. If the router fails, then the other devices will be unable to communicate, but if only one connected device fails, then all other devices will still be able to communicate.
Explanation:
In this type of topology all the computers are connected to a single router through a cable. This router is the central node and all others nodes are connected to the central node.
Answer: Local Area Network (LAN)
Explanation:
A Local Area Network (LAN) is a computer network that interconnects computers within a limited physical area such as a residence, school, laboratory, university campus or office building.
An example of LAN network is "Phone, Computer and TV connected to a single network (such as a Home Network) via Cables, Wifi, Bluetooth or Hotspot". When the devices are interconnected or connected to a LAN, it becomes accessible between each other.
A simplest example of a LAN Device is a <em>Home Router.</em>
<h2>The Examples Of Users:</h2>
<h2>
The Answers Are:</h2>
- Formatted summary of information from a database
- User-friendly interface for adding to or retrieving information from a database
- Stores raw data in a relational database
- Retrieves specific information from a database. Can also be used to update, edit, and remove data
<h2>
Hope it helps*^-^*All Correct!?</h2>
Answer:
answer:
#include <iostream>
#include<list>
using namespace std;
bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;
l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";
/*Display the list*/
cout<<endl; return 0;
}
Answer:
The answer should be data availability
