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Maurinko [17]
2 years ago
13

Find the x and y intercepts 4x-5y=40​

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
7 0

Answer: x = 5/4y + 10

              y = 4/5x - 8

Step-by-step explanation:

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What are thooooossssss
Elina [12.6K]

Answer:

nikes

Step-by-step explanation:

8 0
3 years ago
Point C is reflected across the y-axis. Which point represents the reflection? ANWSER QUICKLY PLEASE!
sp2606 [1]

Answer:

whichever is the same on the y cordanate but not the x cordanate (opsite side of 0)

Step-by-step explanation:

Change the negativity of the first number in the cords are pair then chose that answer that is there

3 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
2 years ago
Three angles of a quadrilateral are 75°, 90° and 75°. What is the measure of the fourth angle?
Sergio039 [100]

the inside of quadrilateral is always 360°.So add 75°,90° and 75° and then subyaract from360°.

x+75°+75°+90°=360

×+240°=360°

x=360°-240°

x=120°

4 0
3 years ago
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