Answer:
-2 : -1
-1 : -1/2
0 : 0
1 : 1/2
2 : 1
3 : 3/2
4 : 2
5 : 5/2
6 : 3
Step-by-step explanation:
Plug in whatever is on the left side of the table to the x in the equation (1/2 x)
Ex. y = 1/2 (4)
y = 2
Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form
is equal to

where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to

if
----> the <u>quadratic equation</u> has two <u>real roots</u>
if
----> the <u>quadratic equation</u> has one <u>real root</u>
if
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
Answer:
−8s4u2+2s2ux+6x2
Step-by-step explanation:
=(6x+8us2)(x+−s2u)
=(6x)(x)+(6x)(−s2u)+(8us2)(x)+(8us2)(−s2u)
=6x2−6s2ux+8s2ux−8s4u2
=−8s4u2+2s2ux+6x2
So we are finding the difference btween 5x-3 and 3x+1.
(5x-3)-(3x+1)
Let's subtract the x's first.
5x-3x=2x
Now the numbers.
-3-1=-4
Now, we need to put 2x and -4 together.
The expression would be 2x-4.
C because it is 2(3/2w +w)=5w