Ask question

Ask question

All categories

3 years ago

10

Given: a-b= c-d, b=d-1, c=6; prove: a=5

1 answer:

Brut [27]3 years ago

6 0

Given :

a-b = c-d ...1)

b = d-1 ...2)

c = 6

To Prove :

a = 5

Solution :

Adding equation 1 and 2, we get :

(a-b) + (b) = (c-d) + (d-1)

a = c -1 ...3)

Putting given value of c = 6 in above equation, we get :

a = 6 - 1

a = 5

Hence, proved.

You might be interested in

NEED ANSWER QUICK, fastest correct answer will be marked brainiest !!!!

makkiz [27]

I’m pretty sure he could only make 1 rectangle with 5cm because it’s an odd number which means he couldn’t stack them on top of each other evenly like he could with the 6cm rectangles, so he’d only be able to line them up next to each other and that’s it (I hope that’s right; sorry if it’s not but it makes sense to me lol)

8 0

4 years ago

PLEASE HELP!!! I REWARD BRAINLIEST! I NEED HELP ASAP!

zimovet [89]

Answer:

1?

Step-by-step explanation:

I think its one...

6 0

3 years ago

Read 2 more answers

Which three values are greater than 1/2? <br> 1/3<br> 45%<br> 0.62<br> 59%<br> 0.315<br> 3/4

Sloan [31]

0.62, 59%, and 3/4
these are all more than 50% which is what 1/2 is.

8 0

3 years ago

Read 2 more answers

Melissa bought 40 books. Melissa bought 8 times as many books as Brian. Let b be the number of books that Brian bought

Kay [80]

Answer:

a) 40 = 8b

b) b = 5

Step-by-step explanation:

(b) 40 = 8 × b

40 ÷ 8 = b

5 = b

4 0

3 years ago

Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat

Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

$T=60+40e^{kt}$

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

$T=60+40e^{kt}$

at T = 90°C and t = 3 minutes

$90=60+40e^{k(3)}$

$30=40e^{3k}$

or

$e^{3k}=\frac{3}{4}$

taking the natural log both sides, we get

3k = $\ln(\frac{3}{4})$

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

$65=60+40e^{( -0.09589)t}$

or

$5=40e^{( -0.09589)t}$

or

$e^{( -0.09589)t}=\frac{5}{40}$

or

$e^{( -0.09589)t}=0.125$

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

6 0

3 years ago