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lys-0071 [83]
2 years ago
10

A clothing manufacturer makes 1,500 pairs of jeans. They ship their jeans to stores in packages of 36. How many full packages wi

ll be used to ship the jeans? How many jeans are left over?
Mathematics
1 answer:
Crazy boy [7]2 years ago
4 0

Answer:

a) How many full packages will be used to ship the jeans?

41 packages

b) How many jeans are left over?

24 Jeans

Step-by-step explanation:

We are told that a manufacturer: made 1500 Jeans and is shipping them in packages of 36.

Hence, the number of packages of 36 he can send out to stores is calculated as:

1500÷ 36

= 41.666666667

In whole number packages = 41 packages

Hence, 41 full packages would be used to ship the jeans.

The number of Jeans left behind is

1500 - (41 × 36)

= 1500 - 1476

= 24 Jeans

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Answer:

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Answer:

$297.70

Step-by-step explanation:

First, find her hourly wage:

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3 years ago
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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

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= 0.3 collisions per  month

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          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}&#10;

                                                           for x ∈ N ∪ {0}

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Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}&#10;

                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

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           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}&#10;

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                =0.2222454662^{2}

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=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

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So,

P(1  collision in 6 month period)

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So,

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   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

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in file

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