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bekas [8.4K]
3 years ago
10

P. 14.1

Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

. a = 15, b = 20 2. a = 5, b = 12

N. 25

U. 9

3. a = 13, b = 84

4. a = 65, b = 72

O. 97

5. a = 6, b = 17.5

6. a = 6-, b = 7

3'

H. 116.6

N. 60

Find the side length b of the right triangle with the given

hypotenuse c and side length a. Round your answer to the

nearest tenth.

G. 30

O. 13

7. c = 61, a = 11

8. C = 82, a = 80dis is the good kid ok

Step-by-step explanation:

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I have no idea how to solve this. I have to teach myself this and I’m stuck. How do I find x?
Valentin [98]
Since the topic is similar right triangles you need to think of the Pythagorean triples, for this problem use the 3-4-5 triplet ratio

8 0
4 years ago
What is the factorization of 3x^2 + 6x - 24 ???
xxTIMURxx [149]

Answer:

3(x-2) (x+4)

Step-by-step explanation:

Factor the polynomial

4 0
3 years ago
Does anyone know how he got from step 1 to step 2??????????
padilas [110]

9514 1404 393

Explanation:

Both sides of the equation are squared.

  \dfrac{x-12}{4}=\sqrt{x} \qquad\text{given}\\\\ \left(\dfrac{x-12}{4}\right)^2=x \qquad\text{square both sides}\\\\ \left(\dfrac{x}{4}-3\right)^2=x \qquad\text{divide out the fraction}\\\\ \dfrac{x^2}{4^2}-\dfrac{6}{4}x+9=x \qquad\text{$(a-b)^2=a^2-2ab+b^2$}\\\\\dfrac{x^2}{16}-\dfrac{5x}{2}+9=0 \qquad\text{subtract $x$}

I like this better without fractions, so would multiply by 16 at this point (or earlier).

  x^2 -40x +144 = 0

  (x -36)(x -4) = 0

  x = 4 or 36 . . . . . . x = 4 is extraneous

The solution is x = 36.

3 0
3 years ago
HELPPPPPP?????????????????,,,,,,,????
eduard
280 cm. Hope this helps!
7 0
3 years ago
Read 2 more answers
Which figure is a counterexample to the following statement?
Artemon [7]

The correct option is D.

Option A. isn't even about quadrilater, so we can immediately discard it.

Option B. statement is true, but has nothing to do with the point of the question. In fact, it is true that every square is in particular a rectangle, but in turn every rectangle is a parallelogram. So, there's no counterexample here

Option C. is false, because a dart is a parallelogram: both of its opposite sides are parallel.

Option D. finally presents a counterexample. In fact, The two bases of a trapezoid are parallel, but the two other sides are not. So, a trapezoid is not a parallelogram, even though it has a pair of parallel sides. This is way, in order to be a parallelogram, it is necessary for the quadrilateral to have two pairs of parallel sides.

4 0
3 years ago
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