Question

9. Find the dimensions of the4 triangular faces of the pyramid.(Height is 55.5 ft)​

Answer 1

Answer:

$Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft$

Step-by-step explanation:

We have a 4-sided triangular pyramid , where

$Q=\frac{\pi}{2}*H\\P=Q*\sqrt{\frac{1}{2}+\frac{4}{\pi ^{2}}}\\Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft$