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3 years ago

9. Find the dimensions of the4 triangular faces of the pyramid.(Height is 55.5 ft)

Mathematics

1 answer:

Minchanka [31]3 years ago

3 0

Answer:

$Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft\\$

Step-by-step explanation:

We have a 4-sided triangular pyramid , where

$Q=\frac{\pi}{2}*H\\P=Q*\sqrt{\frac{1}{2}+\frac{4}{\pi ^{2}}}\\Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft\\$

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