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3 years ago

log property puzzle please I don't understand this at all help help help help help please please please please help help help

Mathematics

1 answer:

docker41 [41]3 years ago

5 0

Answer:

Step-by-step explanation:

The chart doesn’t make much sense. I don’t know why some boxes are complete empty.

Log₃(60) = log₃(6) + log₃(10) = log₃(3) + log₃(20) = log₃(120) - log₃(2) = log₃(240) - log₃(4)

log₇(36) = log₇(18) + log₇(2) = log₇(9) + log₇(4) = log₇(72) - log₇(2) = log₇(144) - log₇(4)

log₆(18) = log₆(9) + log₆(2) = log₆(6) + log₆(3) = log₆(36) - log₆(2) = log₆(54) - log₆(3)

log₂₅(60) = log₂₅(30) + log₂₅(2) = log₂₅(15) + log₂₅(4) = log₂₅(180) - log₂₅(3) = log₂₅(300) - log₂₅(5)

log(40) = log(20) + log(2) = log(8) + log(5) = log(80) - log(2) = log(120) - log(3)

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4 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

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3 years ago

The diameter of a circle is a chord that _____ passes through the center of the circle.

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It always passes through the center.

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3 years ago

Read 2 more answers

The length of a rectangle is 4yd longer than its width. If the perimeter of the rectangle is 72yd, find its length and width.

Brilliant_brown [7]

Suppose the width is w

Then the length will be w+4

Perimeter will be 2 (length + width) = 2 (w + w + 4 ) = 60

Solve this for w. Knowing w you can find the length and width.

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3 years ago

Help me out please asp

Doss [256]

I would say 20

I’m not so totally sure but I believe it’s that because of the ratios, CB:CE is 3:6, and then CA:CT would probably be 10:20. does that make sense?

sorry if i’m incorrect

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3 years ago

log property puzzle please I don't understand this at all help help help help help please please please please help help help​

log property puzzle please I don't understand this at all help help help help help please please please please help help help