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2 years ago

What is the measure of b

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

8 0

Answer:

90-66=24

Step-by-step explanation:

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Fill the blank bellow.....

Lemur [1.5K]

slope = (y2-y1)/(x2-x1)

the first slope is 0 (horizontal line)

second slope is undefined (vertical line)

3 0

3 years ago

A carpenter has at most $250 to spend on lumber the inequality 8x+12y<250 represents the numbers x of 2 by 8 boards and the n

malfutka [58]

Answer:

The carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.

Step-by-step explanation:

Given:

Amount a carpenter can spend at most = $250

The inequality to represent the amount he can spend on each type of board is given as:

$8x+12y$

where $x$ represents '2 by 8 boards' and $y$ represents '4 by 4 boards'.

To determine whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.

Solution :

In order to check whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards' , we need to plugin the $x=12$ and $y=14$ in the given inequality and see if it satisfies the condition or not or in other words (12,14) must be a solution for the inequality.

Plugging in $x=12$ and $y=14$ in the given inequality

$8(12)+12(14)$

$96+168$

$264$

The above statement can never be true and hence the carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.

6 0

3 years ago

Simon has $40 to buy baseballs for her team's practice. Each baseball cost $3. Which inequality represents this situation?

Liula [17]

3b<40 because no matter what the price cannot be over 40 because she only has 40

4 0

3 years ago

Read 2 more answers

SOLVE. integration of (1-v) /(1+v^2)

Nutka1998 [239]

$\displaystyle\int\frac{1-v}{1+v^2}\,\mathrm dv=\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv$

The first integral is already standard and has an antiderivative in terms of $\arctan v$ . For the second integral, take $w=1+v^2$ so that $\dfrac{\mathrm dw}2=v\,\mathrm dv$ . Then

$\displaystyle\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv=\arctan v-\frac12\int\frac{\mathrm dw}w$
$=\arctan v-\dfrac12\ln|w|+C$
$=\arctan v-\dfrac12\ln(1+v^2)+C$

4 0

3 years ago

Please help me with these two questions if you can! Btw happy Tuesday

Ymorist [56]

Answer:

Happy Tuesday! Here i'll explain it:

Step-by-step explanation:

First you will have to make 2 2/5 into a improper fraction and then subtract the 5/6. after you have done that multiply the 3/4 to the number

7 0

2 years ago