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eduard
3 years ago
7

Bob bought 24 hockey tickets for $83. Adult tickets cost $5.50, and child tickets cost $2.00. How many child tickets did he buy

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

14

Step-by-step explanation:

This can be solved by writing 2 equations and solving simultaneously.

Let <em><u>number of Adult tickets be A, and number of child tickets be C.</u></em>

<em><u /></em>

<u><em>"Bob bought 24 hockey tickets":</em></u>

A+C=24

<em><u>"Adult tickets cost $5.50, and child tickets cost $2.00...Bob bought 24 hockey tickets for $83":</u></em>

5.5A+2C=83

Now we can solve the first equation for A and substitute in 2nd equation and get the value of C.

A + C = 24

A = 24 - C

Now,

5.5 A + 2 C = 83

5.5 (24 - C) + 2C = 83

132 - 5.5C + 2C = 83

-3.5 C = 83 - 132

-3.5C = - 49

C = 14

Hence, Bob bought 14 child tickets

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