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3 years ago

I NEED HELP WITH THIS !

Mathematics

1 answer:

Darina [25.2K]3 years ago

8 0

62.85 times so basically 63 times

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if a chocolate cake is divided into six equal and each has 280 calories, how many calories are in the whole cake

Contact [7]

Answer:

1680

Step-by-step explanation:

280 x 6 = 1680

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3 years ago

What did Archimedes discover about the centroid of a triangle? (Site 1)

Anna007 [38]

Answer:

Archimedes showed that the point where the medians are concurrent (the centroid) is the center of gravity of a triangular shape of uniform thickness and density

Step-by-step explanation:

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3 years ago

PLEASE HELP ME IM STRUGGLING!!!

Kitty [74]

Answer:

The required answer is $c=7\sqrt{3}$

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

$\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\$

Substituting the values we get

$\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7$

Now in Triangle ADC Tangent identity we have

$\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}$

Substituting the values we get

$\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}$

The required answer is $c=7\sqrt{3}$

8 0

3 years ago

Find the missing measurement.

laiz [17]

Answer: 9.6 km

Rounding of to nearest tens- 10KM

6 0

4 years ago

Read 2 more answers

Qaudriladrial ABCD had cordinates A (3, 5) B(5, 2) C(8, 4) D(6, 7) qaudriladrial ABCD is a what?

Lorico [155]

The quadrilateral is a square

<h3>What are quadrilaterals?</h3>

Quadrilaterals are polygons, that have four sides and four corners

The coordinates are given as:

A = (3, 5)
B = (5, 2)
C = (8, 4)
D = (6, 7)

Start by calculating the adjacent side lengths using:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$AB = \sqrt{(3- 5)^2 + (5- 2)^2}$

$AB = \sqrt{13}$

$BC = \sqrt{(8- 5)^2 + (4- 2)^2}$

$BC = \sqrt{13}$

The side lengths are equal.

Hence, the quadrilateral is a square