Write the simplified form of (-0.5z + 0.9z) – (-0.3z + 0.9z).
1 answer:
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<h2>Answer with explanation:</h2>
Let p be the proportion of the correct answers.
As per given , we have
, since the alternative hypothesis is right tailed , so the test is a one -tailed test.
If the student gets 52 answers correct out of 80.
i.e. the proportion of correct answers :
Test statistic :
P-value : [ by using p-value table for z (right-tailed)]
Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.
Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.