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Ksju [112]
3 years ago
10

Jessica is going to a vegetable shop. She buys some lady fingers for $23, some potatoes for $30,

Mathematics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

$89

Step-by-step explanation:

add all the numbers together

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Where is the function f(x)=3x^2-6x-45/x^2-5x discontinuous, and what types of discontinuities does it have?
Vedmedyk [2.9K]

Answer:

Below.

Step-by-step explanation:

f(x)=3x^2-6x-45/x^2-5x

= 3x^2-6x-45 / (x(x - 5))

The denominator is zero when x - 0 and x = 5.

So there will be a vertical asymptote  at x = 0 and a hole at x = 5.

If we do the division  we get f(x)  = 3  remainder 9x - 45

so there will also be a horizontal asymptote where x = 3.

5 0
2 years ago
Read 2 more answers
What is the measure of arc WXY
bonufazy [111]

Answer:

152°

Step-by-step explanation:

Let P be any point on tangent \overleftrightarrow{YZ} and WY is secant or chord of the \odot J .

\therefore m\angle WYZ + m\angle WYP = 180°\\(Straight \: line \: \angle 's) \\\therefore 104° + m\angle WYP = 180°\\\therefore  m\angle WYP = 180°- 104° \\\red{\boxed {\bold {\therefore  m\angle WYP = 76°}}} \\

NOW, by tangent secant theorem:

m\angle WYP =\frac{1}{2}\times m(\widehat{WXY}) \\\\76°=\frac{1}{2}\times m( \widehat{WXY}) \\\\76°\times 2 =m( \widehat{WXY}) \\\huge \purple {\boxed {\therefore m(\widehat{WXY}) = 152°}}

8 0
2 years ago
Find a polynomial function with leading coefficient 1 that has the given zeros, multiplicities, and degree. zero: 1, multiplicit
vfiekz [6]

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x-0)^2

The polynomial for the conditions with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicity: 3 Zero: 0, multiplicity: 2 Degree: 5 is given as

According to the given condition

The given conditions to write the polynomial equations are as follows

Zero 2  and Multiplicity 3

Zero 0 and Multiplicity 2  

Degree of polynomial expression  = 5

The leading coefficient of polynomial expression = 1

Let us consider the polynomial equation has only one variable and hence in the general form we can write the equation of polynomial as follows

From the general form of polynomial expression as shown in equation (1) we can write

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x)^2-------(2)

So the polynomial for the conditions given in the question is expressed as

y(x)=1*(x-2)^3(x)^2

For more information on polynomials click on the link below:

brainly.com/question/15702527

#SPJ4

8 0
1 year ago
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

3 0
3 years ago
How many cupcake are in 1/3 dozen
Anettt [7]

4 cupcakes because if you do 12/ 1/.. you do kcf = to 12 x 1/3= 4

your welcome

7 0
3 years ago
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