can someone please help me answer this thank you, will give brainliest if i can just please no spam answers, thank you!

At which value in the domain does f(x)=0 ?

lina2011 [118]

f(x)=0

Domain are the set of x values

f(x)=0 , we find all the x values where y =0

At x intercepts y is always 0

so we find all the x intercepts.

x intercepts are the points where the graph crosses x axis

In the graph we can see that the graph crosses x axis at

-2.5 , -0.75 and 1

-2.5 , -0.75 and 1 are the domain where f(x)=0

5 0

3 years ago

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A car travels 312 miles in the same time that a motorcycle traveled 272. If the cars speed is 10mph more than the motorcycles, f

dimaraw [331]

Answer: speed of the car is 88 miles per hour

the speed of the motorcycle is 78 miles per hour

Step-by-step explanation:

Number of miles travelled by car = 312

Number of miles travelled by motorcycle = 272

Let x = speed of the car

Let y = speed of the motorcycle

If the car's speed is 10mph more than the motorcycle's, it means

x = y + 10 - - -- - - 1

Time taken for car to travel 312 miles is distance /speed = 312/x

Time taken for motorcycle to travel 272 miles is distance /speed = 272/y

The car travels 312 miles in the same time that a motorcycle traveled 272.

This means

312/x = 272/y

312y = 272x

y = 272x/312

Substituting y = 272x/312 into equation 1, it becomes

x = 272x/312 + 10

312x = 272x + 3120

312x-272x = 3120

40x = 3120

x = 3120/40 = 78 miles per hour

x = y + 10 = y + 78

x = 88 miles per hour

3 0

2 years ago

∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the

lora16 [44]

I have attached an image of the triangle.

BC = 9 cm

Answer:

CE = 7.2 cm

Step-by-step explanation:

In the attached triangle, we see that;

AB = AC = 7.5cm

BC = 9 cm

AD = 6cm

BC = 9cm

Formula for area of triangle is given as;

A = ½bh

Where b is base and h is height.

For the ∆ ABC with BC as base,

Area = ½ × 9 × 6 = 27 m²

Similarly, For ∆ ABC with AB as base,

Area = ½ × 7.5 × CE

Now, area from earlier is 27 cm²

Thus;

½ × 7.5 × CE = 27

Multiply both sides by 2 to get;

7.5CE = 54

CE = 54/7.5

CE = 7.2 cm

3 0

2 years ago

I need help with this question!!!

Nuetrik [128]

Answer: B. positive 6

Step-by-step explanation: Addomg the positive number to a negative number would turn it to a positive eventually. So u covert your factions to decimals to better see the resemblance. And 1 1/2 is the same as 1.5, and 2 1/10 is the same as 2.1 but it’s easier to deal with decimals. So then just add the positive to the negative sense 1 1/2 is closer to zero. I hope this helps I’m not the best at explaining things

7 0

2 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

2 years ago

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