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Softa [21]
3 years ago
15

Does this graph represent a function? Why or why not?

Mathematics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

Yes.

Step-by-step explanation:

It is a function because it passes the vertical line test. Each x-value has just one y-value. If the relation had any x-values that had several y-values, it would just be a relation. But this one is a function.

Hope this helps!

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3 packs of soda cost $10 less than 5 packs of soda. Write and equation that models this, and solve.
zysi [14]
<span>Cost 1 pack = x
3x + 10 = 5x
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8 0
3 years ago
The vertices of a triangle are A (-2, 2), B (4,10), and C (0, -2). Find the equation of the line that contains
Tpy6a [65]

Answer:

y = 1/2 x + 3

Step-by-step explanation:

mid point of line BC = (2, 4)

slope of the line containing median (m) = 1/2

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since y = mx + b

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4 0
3 years ago
Which function has a domain of all real numbers except x=π/2 ±nπ?
boyakko [2]
<span>A. y=secx This problem deals with the various trig functions and is looking for those points where they are undefined. Since the only math operations involved is division, that will happen with the associated trig function attempts to divide by zero. So let's look at the functions that are a composite of sin and cos. sin and cos are defined for all real numbers and range in value from -1 to 1. sin is zero for all integral multiples of pi, and cos is zero for all integral multiples of pi plus pi over 2. So the functions that are undefined will be those that divide by cos. tan = sin/cos, which will be undefined for x = π/2 ±nπ cot = cos/sin, which will be undefined for x = ±nπ sec = 1/cos, which will be undefined for x = π/2 ±nπ csc = 1/sin, which will be undefined for x = ±nπ Now let's look at the options and pick the correct one. A. y=secx * There's a division by cos, so this is the correct choice. B. y=cosx * cos is defined over the entire domain, so this is a bad choice. C. y=1/sinx * The division is by sin, not cos. So this is a bad choice. D. y=cotx, * The division is by sin, not cos. So this is a bad choice.</span>
4 0
3 years ago
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igor_vitrenko [27]
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6 0
3 years ago
I need help with 8,9 and 10
rodikova [14]

Answer:

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Question 10 is not visible

8 0
3 years ago
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