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MariettaO [177]
3 years ago
12

+ Extra points, and I will give BRAINLIEST to the first person to get this question right.

Mathematics
1 answer:
Scrat [10]3 years ago
3 0
X = -15

14(-15) + 6
-------------- = - 68
3

-8 + 4(-15) = - 68

So, -3(-15)² - 7 = -682

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The statement ‘5 is added to 9 times a certain number n and the result is 32’ is represented by? *
salantis [7]

Answer:

5+(9×n)=32

n=3

.:.n is represented by 3

3 0
2 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
Thom earns $12.40 per hour at the
kogti [31]

Answer:

$3,645.6

Step-by-step explanation:

1hr=$12.4

42hrs=x

x=$520.8×7 =$3,645.6

7 0
3 years ago
How do you use math every day?
puteri [66]

Answer:

Figuring out distance, time and cost for travel

shopping for the best price

Step-by-step explanation:

7 0
3 years ago
Trigonometric identities: Performance task
MakcuM [25]

#1

\\ \sf\longmapsto (1+cosx)(1-cosx)

\\ \sf\longmapsto 1-cos^2x

\\ \sf\longmapsto sin^2x

#2

\\ \sf\longmapsto \dfrac{1}{cot^2x}-\dfrac{1}{cos^2x}

\\ \sf\longmapsto tan^2x-sec^2x

\\ \sf\longmapsto 1

3 0
3 years ago
Read 2 more answers
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