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Viefleur [7K]
3 years ago
5

50 points , please be honest

Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer:

\sqrt{15}

Step-by-step explanation:

a^2+b^2=c^2

7^2+b^2=8^2

49+b^2=64

b^2=15

b=\sqrt{15}

Greeley [361]3 years ago
5 0

Answer:

7

Step-by-step explanation:

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False, an inscribed angle is not formed by radii.
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3 years ago
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

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Substitute in the given differential equation

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Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

y'=3x^2

y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
3 years ago
Read 2 more answers
Someone who explain me please
kotykmax [81]
First you need to isolate the variable so for #1 I would add 2t on both sides and add 3 on both sides. That makes the inequality -4t<-16. Then divide both sides by -4 to get t<4. This means that t is less than 4 so you need to draw an open circle on four on the number line and draw an arrow pointing to everything less than 4. ( If the inequality is equal to and less than/ greater than a # shade in the circle.)
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3 years ago
Help!!!! I have rsm tomowrrow. can u also show me how to do it? thanks!
Tpy6a [65]

Check the picture below.

6 0
2 years ago
Help plsssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
Harrizon [31]
3 so D
Answer is 119

Hope this helps:)
3 0
3 years ago
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