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2 years ago

Maile is walking around a circular track. if the radius is 100m, how far did she walk if she is 1/3 the way around

1 answer:

7 0

The full length of the circumference is
C = 2πr
C = 2π*100 m ≈ 628.32 m

1/3 that distance is (628.32 m)/3 ≈ 209.44 m

Maile walked about 209.4 m.

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Roxanne has $80 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much will she have

finlep [7]

104 because 10% of 80 is 8 years meaning 8+8+8=24 add 24 to 80 and ur answer is 104

3 0

3 years ago

The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation

Rudiy27

Answer:

consecutive = x+x+2

x+x+2 = 4x-20

2x+2=4x-20

2=2x-20

22=2x

x=11

Numbers are 11,13.

Hope this helps plz hit the crown :D

8 0

2 years ago

What is 35 3/4 divided by 1/8

katrin [286]

35 3/4= 35.75 and 1/8=0.125

35.75/0.125= 286

7 0

3 years ago

Read 2 more answers

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago

If two different planes intersect then they intersect at one and only one line true or false

ivanzaharov [21]

True is the good answer .

8 0

2 years ago