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Nina [5.8K]
3 years ago
13

18x - 5y = -14 9x - Зу = -12I need 2 points (x,y) solve using elimination​

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

x=2

y=10

Step-by-step explanation:

I use Symbolad it helps a lol

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A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
The value of C has to be Greater than 0.65
grin007 [14]

Answer:

1.3

Step-by-step explanation:

1. .65 = .5c ---> .65/.5

2. 1.3 = c

4 0
2 years ago
What are the zeros of the function f(x) = x^4 - x² - 2?
vaieri [72.5K]

Answer:

x= i\\\\ x = -i \\\\x=\sqrt 2\\\\x = -\sqrt 2

Step-by-step explanation:

~~~~~~x^4 -x^2 -2=0\\\\\implies x^2 \cdot x^2-2x^2 +x^2 -2 = 0\\\\\implies x^2(x^2 -2) +(x^2 -2) =0\\\\\implies (x^2 +1)(x^2 -2) = 0\\\\ \implies x^2 +1=0~~~~~~~~\text{or}~~~~~~~~~x^2 -2 = 0\\\\ \implies x = \pm\sqrt{-1}~~~~~~~\text{or}~~~~~~~~~~ x = \pm\sqrt 2\\\\\implies x= \pm i~~~~~~~~~~~~~\text{or}~~~~~~~~~ x= \pm\sqrt 2

7 0
1 year ago
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