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kkurt [141]
3 years ago
7

2 x (c^2 -5) for c=4

Mathematics
2 answers:
Butoxors [25]3 years ago
4 0

Answer:

22

Step-by-step explanation:

PEMDAS

4^2 = 16

16 - 5 = 11

11 x 2 = 22

svlad2 [7]3 years ago
4 0

Answer:

22

Step-by-step explanation:

2 (c^2 -5)

Let c=4

2 (4^2 -5)

PEMDAS

Parentheses first,

(4^2 -5)

Exponents

16-5 =11

Replace into expression

2(11)

22

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There are ten candidates for a job. The search committee will choose three of them, and rank the chosen three from strongest to
saul85 [17]

Answer:

720

Step-by-step explanation:

Since we are choosing a subset of 3 people from a set of 10 people, and arranging the 3 people according to relative strength, the answer can be obtained by computing P(10,3).

 

 P(10,3)=10! / (10-3)!

= 10!/7!

Rewrite  10 !  as  

10 * 9  * 8  * 7 !  / 7!

Cancel the common factor of  7 !  and divide ( 10  * 9 * 8 ) by  1

10  * 9  * 8 = 720

8 0
3 years ago
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Tresset [83]
I would but I don’t know how to explain it all!
8 0
2 years ago
Read 2 more answers
Please answer right!
BARSIC [14]

Answer:

Step-by-step explanation:

5x + 2 - 3x - 1 = 3x + 2

5x - 3x - 3x = - 2 + 1 + 2

5x - 6x = 1

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x = 1 / -1

x = -1

7 0
2 years ago
A right triangle has a leg of 15 feet and a second leg of 24 feet. Find the length of the hypotenuse
Lorico [155]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
2 years ago
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