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2 years ago

PLEASE NEED HELP DUE IN 10 MINUTES??!!

Mathematics

1 answer:

bixtya [17]2 years ago

5 0

Answer:

M<C = 52.4 given

M<G= 52.4

M<B = 127.6

M<D= 127.6

M<K = 52.4

M<N = 52.4

M<H = 127.6

M<M= 127.6

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Use radical notation to rewrite each expression and simplify<br> 9 3/2

scoundrel [369]

Answer:

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Step-by-step explanation:

The fractional exponent m/n is often translated to radical form as ...

$x^{\frac{m}{n}}=\sqrt[n]{x^m}$

In this case, I find it easier to evaluate as ...

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3 years ago

An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the

Sergio039 [100]

Answer:

The estimate is $P__{hat}} \pm E = 0.37 \pm 0.0348$

Step-by-step explanation:

From the question we are told that

The sample size is n = 522

The sample proportion of students would like to talk about school is $\r p__{hat}} = 0.37$

Given that the confidence level is 90 % then the level of significance can be mathematically evaluated as

$\alpha = 100 - 90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } = 1.645$

Generally the margin of error can be mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }$

=> $E = 1.645 * \sqrt{\frac{0.37 (1- 0.37 )}{522 } }$

=> $E = 0.0348$

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is

$P__{hat}} \pm E$

substituting values

$0.37 \pm 0.0348$

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Step-by-step explanation:

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