Yes what the person above me said
Answer:
f ( x ) does not satisfy the mean value theorem
Step-by-step explanation:
The given data :-
- f(x) = 3x - 4 cos ( 2x + 1 )
- f'(x) = 3 +8 sin ( 2x + 1 )
- The interval [ -1 , 2 ]
Solution :-
i) f(x) is continuous on [ -1 , 2 ]
ii) f(x) is derivable on ( -1 , 2 )
f ( -1 ) = 3 * (-1 ) - 4 cos [ 2 * ( -1 ) + 1 ] = - 3 + cos (-1 ) = - 3 - 4 * 0.9998 = - 6.992
f ( 2 ) = 3 * 2 - 4 cos ( 4 * 2 + 1 ) = 6 + 4 cos 9 = 6 - 3.9507 = - 3.04924
iii) f ( -1 ) ≠ f ( 2 )
f ( x ) is not real valued function so it does not satisfy the mean value theorem
It is 639.5. this is how you round numbers to the nearest tenth:
if the digit in the hundredths place is 5 or more you round up one, if it is lower than 5 it stays the same, pay no attention to the thousandths place....ex--> 0.497
the 4 is the tenths place
th 9 is the hundredths place
the 7 is the thousandths place......since 9 is 5 or more you round the 4 up one number, so the 4 would be a 5. pay no attention to the 7. lets do another
0.426
the 4 stays as a 4 because 2 is a lower number than 5.
All the 5 angles are equal to 286, so....
360 - 286 = 74
then,
180 aka a straight line
180 - 74 = 106
interior is 74
exterior is 106
Answer:
I guess this is the answer