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musickatia [10]
2 years ago
11

16=-(y+3) Find what y is

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
8 0

Answer:

isolate the variable by dividing each side by factors that don't contain the variable ..... answer is y =-19     :)

Step-by-step explanation:

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The weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 l
joja [24]

1. Know what you're looking for:

The range is the difference between the lowest and highest values.

Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.


2. Calculate your lowest and highest values :


Lowest : 145.2 - 0.3 = 144.9 lbs

Highest : 145.2 + 0.3 = 145.5 lbs


3. Calculate the range of actual weights of the object :


145.5 - 144.9 = 0.6 lbs


--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>


There you go! I really hope this helped, if there's anything just let me know! :)

4 0
3 years ago
In the diagram, if KL=10, and MK=2, and JM=6 determine the value of MN. Show your work or explain how you arrived at your answer
kodGreya [7K]

Answer:

6

Step-by-step explanation:

JM is 6 riiite

and JMN should be an equilateral triangle so

4 0
3 years ago
What is the measure of the missing angle
Oduvanchick [21]

Answer:

40 degrees!

Step-by-step explanation:

95 + 45 = 140

180 - 140 = 40

8 0
3 years ago
C. Look for Relationships How do the processes you used for parts A and B differ? How are they the same?
olga_2 [115]

Step-by-step explanation:

Relationship is a ver beautiful friend one answer

5 0
2 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
Read 2 more answers
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