If you add a value to the outcome of the function (as in case a), you will just shift the graph up along the y-axis. Makes sense, right, since you're adding an extra 2 to the value you will plot on the y axis.
If you subtract (in this example) a value to the input of the function, you're actually "looking back" into the past of the graph (i.e., the left side). For example, for x=4 you're now plotting the value that used to be at x=1. So this shifts the graph to the right.
That may be confusing at first. But I hope with a little thought experiment, you get it.
Answer:

Step-by-step explanation:
Considering the function:

The independent variable is "x" and we are asked to model it in terms of the variable "y":

Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.
Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":

Answer:
m=3
Step-by-step explanation:
rise/run or y/x
using the y coords/x coords
15-0/-3-(-8)
=15/-3+8
=15/5
=3
Answer:
X = 28
Step-by-step explanation:
Answer:
The solution to the algebra equation is 4.
Step-by-step explanation:
We are given the equation 5+2b=13. We need to isolate the variable.
First, use subtraction property of equality and subtract 5 from both sides of the equation.
Thus, 2b=8
Now, use division property of equality and divide both sides of the equation by 2.
All things put into consideration, the solution to the algebra equation is 4.
I hope this helped!!
~ Penny