<em><u>An inequality that shows the distance Johnathan could of ran any day this week is:</u></em>
<em><u>Solution:</u></em>
Let "x" be the distance Johnathan can run any day of this week
Given that,
Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles
Therefore,
Number of days ran = 5
The most he ran in 1 day = 3.5 miles
Thus, the maximum distance he ran in a week is given as:
The maximum distance he ran in a week is 17.5 miles
If we let x be the distance he can run any day of this week then, we get a inequality as:
If we let y be the total distance he can travel in a week then, we may express it as,
Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
Answer:
what are the other drop down menus
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
-33
Step-by-step explanation:
well you can use mid point formula and solve for x
or count how many it takes to get from -3 to 27 and add that to -3 the other direction
