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Julli [10]
3 years ago
12

A 500-kilogram horse runs at 5 meters/second. The horse’s kinetic energy is (blank)joulese g = 9.8 N/kg.)

Mathematics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

KE = 6250 Joule.

Step-by-step explanation:

Every moving body has kinetic energy and it is given by the expression

KE = \frac{1}{2}mv^{2}

where the moving body has m as the mass and v as the velocity.

If m is in Kg and v is in meter/sec, then KE will be expressed in Joule.

Now, in this case, m = 500 and v = 5 meter/sec.

So, KE = \frac{1}{2} \times 500 \times (5)^{2} = 6250 Joule. (Answer)

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Does 1/8 ÷ 5 equal 1/4 true or false?​
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On the coordinate plan, what is the distance between the points (−5, 2) and (−5, −10)? A) 7 B) 10 C) 12 D) 15
melomori [17]

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3 years ago
Find each percent change. Round to the nearest tenth of a percent. State if it is an increase or decrease. From 79 miles to 84 m
PolarNik [594]

Answer:

the answer is d.

Step-by-step explanation:

first, you want to use the formula,

new value - original value

<u>____________________</u>

         original value              * 100

you see that 84 is the new value and 79 would be the original value. substitute the numbers in. this is a increase since you will get a positive value.

84 - 79

<u>______</u>

   79      * 100

now we solve it.

5

<u>__</u>

79  * 100

you can either solve the fraction first then multiply that by 100 or multiply the numerator by 100 first then divide that by 79, each way works.

500

<u>____</u>

 79   =  approximately 6.3% increase (this is not a exact value, just rounded)

      or

5

<u>__</u>

79  = approximately 0.063 (this is not a exact value, just rounded)

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7 0
3 years ago
In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

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Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
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