All categories

3 years ago

Evaluate: 30 - 21 ÷ 3 x 2

Mathematics

2 answers:

Delvig [45]3 years ago

8 0

Answer:

Step-by-step explanation:

30 - 21 ÷ 3 x 2 = 16

30 - 7 x 2

30 - 14

wariber [46]3 years ago

5 0

Answer:

Step-by-step explanation:

30-21=9

9/3=3

3x2=6

You might be interested in

Use this cart for my last question I posted!!

Hatshy [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find the measure of

Ivenika [448]

Answer:

The measure of angle BAC is 20°

Step-by-step explanation:

step 1

Find the measure of arc BC

we have that

m∠BOC=arc BC ------> by central angle

we have

m∠BOC=40°

therefore

arc BC=40°

step 2

Find the measure of angle BAC

we know that

The inscribed angle is half that of the arc it comprises

m∠BAC=(1/2)[arc BC]

we have

arc BC=40°

substitute

m∠BAC=(1/2)[40°] =20°

3 0

4 years ago

Read 2 more answers

a coin is tossed and a die is rolled. Find the probability of tossing a tail and then rolling a number greater than 2

rodikova [14]

Answer:

1/3; 33% chance

Step-by-step explanation:

1/2 (prob. of tossing tails) * 2/3 (prob of rolling < 2) = 1/3

5 0

3 years ago

The probability of it snowing on a given day is 4 솎<br>What is the probability of it not snowing?

Sindrei [870]

Answer:

Step-by-step explanation:

Semoga membantu anda anda sekalian

bye vangkee

6 0

3 years ago

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

givi [52]

Answer:

$\mathbf{V = [\dfrac{ 8 \pi }{3}] }$

Step-by-step explanation:

Given that:

y = 6x - x² , y = 8 about x = 2

To find the volume of the region bounded by the curves about x = 2; we have the radius of the cylindrical shell to be x - 1, the circumference to be 2 π (x -2 ) and the height to be 6x - x² - 8

6x - x² - 8

6x - x² - 8 = 0

-x² + 6x - 8 = 0

x² - 6x + 8 = 0

(x -4) (x - 2 ) = 0

So;

x = 2 , x = 4

Thus, the region bound of the integral are from a = 2 and b = 4

Therefore , the volume of the solid can be computed as :

$V = \int \limits ^b _a \ 2x \times f(x) \ dx$

$V = \int \limits ^4_2 2 \pi (x -2) (6x -x^2 -8) \ dx$

$V = 2 \pi \int \limits ^4_2 (6x^2 - x^3 -8x -12 x - 2x^2 +16) \ dx$

$V = 2 \pi \int \limits ^4_2 (8x^2 -x^3-20x +16) \ dx$

$V = 2 \pi \int \limits ^4_2 ( -x^3+8x^2-20x +16) \ dx$

$V = 2 \pi [\dfrac{ -x^7}{4}+\dfrac{8x^3}{3} -\dfrac{20x^2}{2} +16x]^4_2$

$V = 2 \pi [\dfrac{ -(4^4-2^4)}{4}+\dfrac{8(4^3-2^3)}{3} -\dfrac{20(4^2-2^2)}{2} +16(4-2) ]^4_2$

$V = 2 \pi [\dfrac{ -(256-16)}{4}+\dfrac{8(64-8)}{3} -10(16-4)} +16(2) ]$

$V = 2 \pi [\dfrac{ 4}{3}]$

$\mathbf{V = [\dfrac{ 8 \pi }{3}] }$

8 0

3 years ago

Read 2 more answers