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alexdok [17]
3 years ago
9

The area of a rectangular classroom is 572 square feet.

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0

Answer: 26 Feet

Hope this helps!

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2 numbers whose sum is 832
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416 + 416 would = 832
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Identify the range of the graphed function
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Answer: The first Option.

Step-by-step explanation:

y is greater than -1 and y is less than or equal to 4.

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Floyd is an aspiring music artist. He has a record contract that plays him a rate of $200 per month and an additional $12 each a
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he sold 37 albums

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Under normal conditions , 1.5 feet of snow will melt into 2 inches of water . After a monster snowstorm , there were 3.5 feet of
vlabodo [156]
In this question, you need to convert the height of snow into the height of water. To answer this question, it would be easier to find the ratio of snow: water. If 1.5 feet of snow become 2 inch of water, then the ratio would be 2/1.5= 1 1/3.
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5 0
4 years ago
Two dice are rolled; find the probability of rolling a doubles (2 of a kind) or getting two numbers whose sum is equal to 8.
emmainna [20.7K]

Answer:

The probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.

Step-by-step explanation:

There are a total of <em>N</em> = 36 outcomes when rolling two fair dice.

The outcomes for rolling doubles are: {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}.

So, n (Doubles) = n (D) = 6

The outcomes for rolling a sum of 8 are: {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}

So, n (Sum 8) = n (S8) = 5

Considering the outcomes of the above two events, it can be seen that there is a common outcome, i.e. (4, 4).

So, n (D ∩ S8) = 1

Compute the probability of rolling a doubles or getting two numbers whose sum is equal to 8 as follows:

P(D\cup S8)=P(D)+P(S8)-P(D\cap S8)

                 =\frac{n(D)}{N}+\frac{n(S8)}{N}-\frac{n(D\cap S8)}{N}\\\\=\frac{6}{36}+\frac{5}{36}-\frac{1}{36}\\\\=\frac{6+5-1}{36}\\\\=\frac{10}{36}\\\\=0.278

Thus, the probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.

4 0
3 years ago
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