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3 years ago

Which situation can be represented by the expression -2+(-1) Choose 1 Answer:

Mathematics

2 answers:

Brums [2.3K]3 years ago

6 0

Definitely (A). he was already under 2 and then went down an additional 1.

Llana [10]3 years ago

3 0

Answer:

Step-by-step explanation:

I checked on khan

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2x + 6y= 386<br> 4x +4y=292

Vilka [71]

Answer:

x = 13 ,y = 60

Step-by-step explanation:

Solve the following system:

{2 x + 6 y = 386 | (equation 1)

4 x + 4 y = 292 | (equation 2)

Swap equation 1 with equation 2:

{4 x + 4 y = 292 | (equation 1)

2 x + 6 y = 386 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{4 x + 4 y = 292 | (equation 1)

0 x+4 y = 240 | (equation 2)

Divide equation 1 by 4:

{x + y = 73 | (equation 1)

0 x+4 y = 240 | (equation 2)

Divide equation 2 by 4:

{x + y = 73 | (equation 1)

0 x+y = 60 | (equation 2)

Subtract equation 2 from equation 1:

{x+0 y = 13 | (equation 1)

0 x+y = 60 | (equation 2)

Collect results:

Answer: {x = 13 ,y = 60

3 0

3 years ago

a trapezoid has an area of 50 square inches. The bases are 3 inches and 7 inches. What is the height of the trapezoid.

charle [14.2K]

Answer: The answer is 10 inches.

Step-by-step explanation: Given that the area of a trapezoid is 50 square inches and the bases are 3 inches and 7 inches. We are to find the height of the trapezoid.

We know that the area of a trapezoid with height 'h' and bases 'a' inches and 'b' inches is given by

$A=\dfrac{a+b}{2}h.$

In the given question,

a = 3 inches, b = 7 inches, A = 50 square inches, h = ?

Therefore,

$50=\dfrac{3+7}{2}\times h\\\\\\\Rightarrow 50=5h\\\\\Rightarrow h=10.$

Thus, the required height is 10 inches.

8 0

3 years ago

4. As part of a promotion for a new type of cracker, free samples are offered to shoppers in a local supermarket. The probabilit

RUDIKE [14]

Answer:

For this case we need to check the conditions in order to use the normal approximation:

1) $np = 60*0.3= 18>10$

2) $n(1-p) = 60*(1-0.3)= 42>10$

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

$\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean would be given by:

$\mu_{\hat p}=0.3$

And the deviation is given by:

$\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592$

Step-by-step explanation:

For this case we know the following info:

n =60 represent the sample size

$\hat p = 0.3$ represent the estimated proportion of people that will buy a packet of crackers after tasting

For this case we need to check the conditions in order to use the normal approximation:

1) $np = 60*0.3= 18>10$

2) $n(1-p) = 60*(1-0.3)= 42>10$

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

$\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean would be given by:

$\mu_{\hat p}=0.3$

And the deviation is given by:

$\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592$

6 0

3 years ago

This is how many classes students at Bronx College take this semester with the probabilities courses1 2 3 4 5 probability (distr

Annette [7]

Answer:

Step-by-step explanation:

Given the question above :

The probability distribution :

X : ___ 1 ___ 2 ___ 3 ___ 4 ____ 5

P(x): _ 0.1 __ 0.1 __ 0.6 _ 0.1 __ 0.1

The Variance : Var(X) = (Σx²*p(x)) - μ²

μ = E(X) = Σ(X * p(x)) :

Σ(X * p(x)) = (1*0.1)+(2*0.1)+(3*0.6)+(4*0.1)+(5*0.1)

μ = 3

Var(X): [(1^2*0.1)+(2^2*0.1)+(3^2*0.6)+(4^2*0.1)+(5^2*0.1)] - 3²

= 10 - 9

= 1

Hence. Variance = 1

5 0

3 years ago

Twenty-one and four hundred six thousandths Which one is tens , ones , tenths , hundredths , thousandths

Allisa [31]

Six is thousandths four is hunderdths one is ones and tens is 20 i think

3 0

4 years ago