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3 years ago

Help 50 points and brainleist

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

7 0

Answer:

-0/5

Step-by-step explanation:

-2.5 by 1/5 (0.2)

UkoKoshka [18]3 years ago

3 0

Answer: -0.5c

Step-by-step explanation: multiply -2.5 by 1/5 (0.2) and you get -0/5

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A right rectangular prism has a length of 214 cm, width of 8 cm, and height of 2012 cm.

Amiraneli [1.4K]

The volume is 214*8*2012
=3,444,544

4 0

3 years ago

What are the next three terms of each sequence?5,7.5

leva [86]

Answer:

The next three terms are 10, 12.5 and 15

Step-by-step explanation:

I. As you can see 5 and 7.5 is came from 5, 5 + 2.5

So given y = 5 + 2.5( x - 1 ) when y is output, x is term

II. Perform x = 3, 4, 5

So y = 5 + 2.5( 3 - 1 )

= 5 + 5

3rd = 10

y = 5 + 2.5( 4 - 1 )

= 5 + 7.5

4th = 12.5

y = 5 + 2.5 (5 - 1)

= 5 + 10

5th = 15

Leave comment below.

3 0

3 years ago

X + 3 < 15<br> what is 4

professor190 [17]

Answer:

X = > 12 because 15 - 3 = 12 and if X was more than 12 it would be wrong.

Step-by-step explanation:

6 0

3 years ago

39 is what percent of 156

Romashka-Z-Leto [24]

39 is 25% of 156.
Work: 156 x 0.25 = 39 which means that 25% of 156 is 39.

Hope this helps and please mark as brainliest!

8 0

3 years ago

can someone show me how to find the general solution of the differential equations? really need to know how to do it for the upc

mariarad [96]

The first equation is linear:

$x\dfrac{\mathrm dy}{\mathrm dx}-y=x^2\sin x$

Divide through by $x^2$ to get

$\dfrac1x\dfrac{\mathrm dy}{\mathrm dx}-\dfrac1{x^2}y=\sin x$

and notice that the left hand side can be consolidated as a derivative of a product. After doing so, you can integrate both sides and solve for $y$ .

$\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1xy\right]=\sin x$
$\implies\dfrac1xy=\displaystyle\int\sin x\,\mathrm dx=-\cos x+C$
$\implies y=-x\cos x+Cx$

- - -

The second equation is also linear:

$x^2y'+x(x+2)y=e^x$

Multiply both sides by $e^x$ to get

$x^2e^xy'+x(x+2)e^xy=e^{2x}$

and recall that $(x^2e^x)'=2xe^x+x^2e^x=x(x+2)e^x$ , so we can write

$(x^2e^xy)'=e^{2x}$
$\implies x^2e^xy=\displaystyle\int e^{2x}\,\mathrm dx=\frac12e^{2x}+C$
$\implies y=\dfrac{e^x}{2x^2}+\dfrac C{x^2e^x}$

- - -

Yet another linear ODE:

$\cos x\dfrac{\mathrm dy}{\mathrm dx}+\sin x\,y=1$

Divide through by $\cos^2x$ , giving

$\dfrac1{\cos x}\dfrac{\mathrm dy}{\mathrm dx}+\dfrac{\sin x}{\cos^2x}y=\dfrac1{\cos^2x}$
$\sec x\dfrac{\mathrm dy}{\mathrm dx}+\sec x\tan x\,y=\sec^2x$
$\dfrac{\mathrm d}{\mathrm dx}[\sec x\,y]=\sec^2x$
$\implies\sec x\,y=\displaystyle\int\sec^2x\,\mathrm dx=\tan x+C$
$\implies y=\cos x\tan x+C\cos x$
$y=\sin x+C\cos x$

- - -

In case the steps where we multiply or divide through by a certain factor weren't clear enough, those steps follow from the procedure for finding an integrating factor. We start with the linear equation

$a(x)y'(x)+b(x)y(x)=c(x)$

then rewrite it as

$y'(x)=\dfrac{b(x)}{a(x)}y(x)=\dfrac{c(x)}{a(x)}\iff y'(x)+P(x)y(x)=Q(x)$

The integrating factor is a function $\mu(x)$ such that

$\mu(x)y'(x)+\mu(x)P(x)y(x)=(\mu(x)y(x))'$

which requires that

$\mu(x)P(x)=\mu'(x)$

This is a separable ODE, so solving for $\mu$ we have

$\mu(x)P(x)=\dfrac{\mathrm d\mu(x)}{\mathrm dx}\iff\dfrac{\mathrm d\mu(x)}{\mu(x)}=P(x)\,\mathrm dx$
$\implies\ln|\mu(x)|=\displaystyle\int P(x)\,\mathrm dx$
$\implies\mu(x)=\exp\left(\displaystyle\int P(x)\,\mathrm dx\right)$

and so on.

6 0

4 years ago