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11111nata11111 [884]
2 years ago
7

7/12 - □ = 1/6□ = ________​

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
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A circular mirror is surrounded by a square metal frame. The radius of the mirror is 2x. The side length of the metal frame is 8
Schach [20]

Answer:

183.43x2

Step-by-step explanation:

Area of the entire frame = (14x)2 = 196x2

Area of the mirror = pi(2x)2 = 4x2(pi)

Area of the frame surrounding the mirror = (196 - 4pi)x2 = 183.43x2

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2 years ago
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Step-by-step explanation:

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2 years ago
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Points A,M and P are collinear with M in between A and P. If AP=29, AM =5x-3 and MP=8x+6, what does MP=?
charle [14.2K]

The length of MP is 22 units.

<h3>What is a Line Segment?</h3>

A line segment is defined as a measured path between two places. Line segments can make up any polygon's sides because they have a set length.

The figure is given below shows a line segment AP, where the length of line segment AP refers to the distance between its endpoints, A and P.

Given that Points A, M and P are collinear with M in between A and P.

AP=29, AM =5x-3 and MP=8x+6,

A______________M______________P

⇒ AP = AM + MP

Substitute the values of AP = 29, AM =5x-3 and MP=8x+6,

⇒ 29 = 5x - 3 + 8x+6,

Rearranging the terms in the above equation,

⇒ 5x + 8x = 29 + 3 - 6

⇒ 13x = 26,

⇒ x = 26/13,

⇒ x = 2

So MP = 8x+6

Substitute the value of x = 2 in the above equation,

⇒ MP = 8(2) + 6

⇒ MP = 22

Hence, the length of MP is 22 units.

Learn more about the line segment here:

brainly.com/question/25727583

#SPJ1

6 0
2 years ago
Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b
Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A =  (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

Slope, m \, of \. base, \, AC= \frac{dy}{dx}  = \frac{b - b}{a - (-a)}  = \frac{0}{2\cdot a} = 0

Hence, segment AC is vertical

Slope, m \, of \, segment \ CP \,  joining \, vertex, \, to \, midpoint, P, on  \,AC = \frac{0 - b}{0 - 0}  = \frac{-b}{0} = Undifined.

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

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3 years ago
Find the missing value to the nearest hundredth. COS x = 7/14
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