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mina [271]
3 years ago
10

Which statement correctly descibes what happens to the shape and location of the graph of y=2x^2 if it is regraphed as y=-1/2x^2

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Sedbober [7]3 years ago
3 0

Answer:

I got the same question rn

Step-by-step explanation:

What did you end up with for the answer?

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simplify 5ab+9a-ab-7a and justify each step as associative , distributive, commutative, or additive property.
Vladimir [108]

Answer:

5ab-ab+9a-7a

ab(5-1)+a(9-7)

4ab+2a

a(4b+2)

7 0
3 years ago
12e^5 divide by 3e^3
Paladinen [302]

The answer would be <em>29.5562243957</em>.

5 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
4 years ago
40 POINTS + BRAINLIEST!
kotegsom [21]
Asnwer:
15 Units
Hope this helps! :)
4 0
3 years ago
Read 2 more answers
Help picture below problem 16
kirill115 [55]

Answer:

Regular Hexagon

Step-by-step explanation:

There are six sides and all sides are equal

8 0
3 years ago
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